jika h(x) = (nx² - 3x + 1)² dan h''(1) = 2, nilai n =
Matematika
YSJ77
Pertanyaan
jika h(x) = (nx² - 3x + 1)² dan h''(1) = 2, nilai n =
2 Jawaban
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1. Jawaban 4LL
Langsung aja y
h(x) = (nx² - 3x + 1)²
h(x) = (nx² - 3x + 1)(nx² - 3x + 1)
h(x) = n²x⁴ - 3nx³ + nx² - 3nx³ + 9x² - 3x + nx² - 3x + 1
h(x) = n²x⁴ - 6nx³ + 2nx² + 9x² - 6x + 1
h'(x) = 4n²x³ - 18nx² + 4nx + 18x - 6
h"(x) = 12n²x² - 36nx + 4n + 18
h"(1) = 12n²(1)² - 36(1) + 4n + 18
2 = 12n² - 36n + 4n + 18
12n² - 32n + 18-2 = 0
12n² - 32n + 16 = 0 (÷4)
3n² - 8n + 4 = 0
(3n - 2)(n - 2) = 0
n = ⅔ dan n = 2
Semoga berguna +_+ -
2. Jawaban arsetpopeye
h(x) = (nx^2 - 3x + 1)^2
h(x) = (nx^2 - 3x + 1)(nx^2 - 3x + 1)
h(x) = n^2 x^4 - 3nx^3 + nx^2 - 3nx^3 + 9x^2 - 3x + nx^2 - 3x + 1
h(x) = n^2 x^4 - 6nx^3 + 2nx^2 + 9x^2 - 6x + 1
h'(x) = 4n^2 x^3 - 18n x^2 + 4nx + 18x - 6
h''(x) = 12n^2 x^2 - 36n x + 4n + 18
h''(1) = 12n^2 (1)^2 - 36n (1) + 4n + 18
2 = 12n^2 - 36n + 4n + 18
0 = 12n^2 - 32n + 16 =====> bagi 4
3n^2 - 8n + 4 = 0
(3n - 2)(n - 2) = 0
n = 2/3 atau n = 2