Tentukan nilai limit fungsi trigonometri berikut A. Lim x → phi/2 1 - cos 2x / 2 cos x B. Lim x → 0 Cos x + cos 3x / 1 - cos 2x

Limit trigonometri

1)
lim(x->pi/2)  (1  - cos 2x )/ (2 cos x)
x= pi/2 --> (1 - cos 2(pi/2)) / 2 cos pi/2
= (1 - cos pi)/ (2 cos pi/2)
= (1 - (-1)/ (2. 0)
= 2/0
= ~

2)
lim(x->0) (cos x + cos 3x) / (1 - cos 2x)
sub x = 0
limit = (cos 0+ cos 0)/ (1 - cos 0)
limit = (1 + 1)/ (1 -1)
limit = 2/0
limit = ~