persamaan garis singgung kurva y=x^2+x-2 pada titik koordinat 4 adalah... A. y = -5x - 11 B. y = 5x - 6 C. y = -5x + 19 D. y = -5x - 11 atau y = 5x - 6 E. y = 5

y = x^2 + x - 2 => ordinat = 4 => y = 4
4 = x^2 + x - 2
0 = x^2 + x - 6
(x + 3)(x - 2) = 0
x = -3 atau x = 2
(-3,4) atau (2,4)
y = x^2 + x - 2
m = y' = 2x + 1
1) di titik (-3,4) => m = 2(-3) + 1 = -5
y - y1 = m(x - x1)
y - 4 = -5(x - (-3))
y - 4 = -5x - 15
y = -5x - 11
2) di titik (2,4) => m = 2(2) + 1 = 5
y - y1 = m(x - x1)
y - 4 = 5(x - 2)
y - 4 = 5x - 10
y = 5x - 6