jika 4∫1 f(x) dx = 6, maka 4∫1 f(5-x)dx =

Intergral

∫f(x) = F(x)

₁⁴∫ f(x) dx = 6 --> F(4) - F(1)= 6

₁⁴∫f(5-x) dx = F(5-4) - F(5-1) = F(1) - F(4) = - { F(4) - F(1)} = - 6