Help dg proses mencarinya ya...

2log x - (1/x)log(1/2) ≥ 0
2log x - (x^-1)log(2^-1) ≥ 0
2log x - xlog 2 ≥ 0
2logx - 1/(2log x) ≥ 0
Misal 2log x = a
a - 1/a ≥ 0
(a^2 - 1)/a ≥ 0
(a + 1)(a - 1)/a ≥ 0
a = -1 atau a = 1 atau a = 0
Garis bilangan
--- [-1] +++ (0) ---- [1] +++
-1 ≤ a < 0 atau a > 1
2log 2^-1 ≤ 2log x < 2log 2^0 atau 2log x > 2log 2^1
1/2 ≤ x < 1 atau x > 2