Jumlah dari akar-akarv persamaan berikut dengan jawaban yang sesui (Pers.Eksponen) 1.. 2 ∧2x+1-9.2 ∧x+1 +256=0 2. (2x ∧2-13x+15) ∧x-3 = (x ∧2 -4x +1) ∧x-3

1) 2^(2x + 1) - 9 . 2^(x + 1) + 256 = 0
2^(2x + 2 - 1) - 9 . 2^(x + 1) + 256 = 0
2^(2x + 2) . (2^-1) - 9 . 2^(x + 1) + 256 = 0
(2^(x + 1))^2 . 1/2 - 9 . 2^(x + 1) + 256 = 0
Misal 2^(x + 1) = p
p^2 . 1/2 - 9 p + 256 = 0 ======> kali 2
p^2 - 18p + 512 = 0
p1.p2 = c/a
2^(x1 + 1) . 2^(x2 + 1) = 512/1
2^(x1 + 1 + x2 + 1) = 512
2^(x1 + x2 + 2) = 2^9
x1 + x2 + 2 = 9
x1 + x2 = 7

2) (2x^2 - 13x + 15)^(x - 3) = (x^2 - 4x + 1)^(x - 3)
A) x - 3 = 0 => x = 3
B) 2x^2 - 13x + 15 = x^2 - 4x + 1
x^2 - 9x + 14 = 0
(x - 7)(x - 2) = 0
x = 7 atau x = 2
Jadi jumlah x nya adalah 3 + 7 + 2 = 12