jika f(x) (2x+ 3/vx^3)^2 maka f'(x)=

Langsung aja y

f(x) = (2x + 3 / √x³)²
f(x) = 2x² + 9 / x^1/6

f'(x) = 2.2x + 0 / 1/6.x^1/6 - 6/6
f'(x) = 4x / (1/6x^-5/6)
f'(x) = 4x : (1/6 / x^5/6)
f'(x) = 4x × x^5/6 / 1/6
f'(x) = 4x^11/6 / 1/6
f'(x) = 4x^11/6 × 6
f'(x) = 24x^11/6

Semoga berguna +_+