diketahui ΔKLM dengan LM=10cm,KM=4√3cm dan ∠K=60°.Tentukan cos L?

[tex] \frac{LM}{sin \ K} = \frac{KM}{sin \ L} \\ \\ \frac{10}{sin \ 60} = \frac{4 \sqrt{3} }{sin \ L} \\ \\ 10 \ sin \ L= \frac{1}{2} \sqrt{3} \ . \ 4 \sqrt{3} \\ \\ sin \ L= \frac{6}{10} \\ \\ sin = \frac{y}{r} \\ cos = \frac{x}{r} \\ \\ x = \sqrt{10 ^{2} -6 ^{2} }= \sqrt{64}=8 \\ \\ cos= \frac{8}{10} [/tex]