tanpa menggunakan tabel sin 150°+sin 210°/cos 225° - cos 330°
Matematika
batarikamila
Pertanyaan
tanpa menggunakan tabel
sin 150°+sin 210°/cos 225° - cos 330°
sin 150°+sin 210°/cos 225° - cos 330°
1 Jawaban
-
1. Jawaban IfahNurAzizah
[sin150+sin210]/[cos225-cos330]
=[sin(180-150)+(-sin(180+30))]/[-cos(180+45)-cos(360-330)]
=[sin30+(-sin30)]/[-cos45-cos30]
=[1/2 + (-1/2)]/[(-1/2 √2)-1/2 √3]
=0/ [(-1/2√2)-1/2√3]
=0