Matematika

Pertanyaan

tanpa menggunakan tabel
sin 150°+sin 210°/cos 225° - cos 330°

1 Jawaban

  • [sin150+sin210]/[cos225-cos330]
    =[sin(180-150)+(-sin(180+30))]/[-cos(180+45)-cos(360-330)]
    =[sin30+(-sin30)]/[-cos45-cos30]
    =[1/2 + (-1/2)]/[(-1/2 √2)-1/2 √3]
    =0/ [(-1/2√2)-1/2√3]
    =0

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