rubah bilangan biner (II0II0I)2 ke bilangan desimal?

1101101 basis 2 => desimal.

1 =  [tex]1 . 2^{0} [/tex] = 1
0 =  [tex]0 . 2^{1} [/tex] = 0
1 =  [tex]1 . 2^{2} [/tex] = 4
1 =  [tex]1 . 2^{3} [/tex] = 8
0 =  [tex]0 . 2^{4} [/tex] = 0
1 =  [tex]1 . 2^{5} [/tex] = 16
1 =  [tex]1 . 2^{6} [/tex] = 32

1 + 0 + 4 + 8 + 0 + 32 +64 = 109