SBMPTN

Pertanyaan

No 14 sama no 15 pembahasannya ya
Makasih sebelumnya
No 14 sama no 15 pembahasannya ya Makasih sebelumnya

2 Jawaban

  • Cukup menggunakan sifat dasar eksponen dan logaritma
    Gambar lampiran jawaban ernestosihombing
    Gambar lampiran jawaban ernestosihombing
  • 14) sifat logaritma :
    1) (xlog b)/(xlog a) = alog b
    2) a^(alog b) = b

    a = (5log3)/(5log4) = 4log3 = (2^2)log3 = 1/2 . 2log3

    2^a = 2^(1/2 . 2log3) = (2^(2log3))^1/2 = (3)^1/2 = √3

    (2^3a - 2^-3a)/(2^a + 2^-a)
    = ((2^a)^3 - 1/(2^a)^3) / (2^a + 1/(2^a))
    = (√3^3 - 1/(√3^3)) / (√3 + 1/√3)
    = (3√3 - 1/(3√3)) / (√3 + 1/√3) . (√3)/(√3)
    = (9 - 1/3) / (3 + 1)
    = (26/3) / 4
    = 26/12
    = 13/6

    15) blog a = 2 => a = b^2 => a^3 = (b^2)^3 => a^3 = b^6
    blog (c + 3) = 6 => (c + 3) = b^6 => (c + 3) = a^3
    alog (2c + 1) = 3
    => (2c + 1) = a^3
    => (2c + 1) = (c + 3)
    => 2c - c = 3 - 1
    => c = 2