tolong no 1 sama 2... makasih

Kita gunakan L'hospital saja ya (turunan) dan INGAT
y = √f(x) => y' = (f'(x)) / 2√(f(x))

1) Lim (√x - √(2x - 1)) / (x - 1)
= Lim {1/(2√x) - 2/(2√(2x - 1))} / 1
= 1/(2√1) - 2/(2√(2.1-1))
= 1/2 - 2/2
= -1/2

2) Lim (x - √(2x + 3)) / (x^2 - 9)
= Lim (1 - 2/(2√(2x + 3))) / (2x)
= Lim (1 - 1/√(2x + 3)) / (2x)
= (1 - 1/√(2.3 + 3)) / (2.3)
= (1 - 1/3) / 6
= (2/3) / 6
= 2/18
= 1/9