Hitunglah nulai limit fungsi berikut A. Lim x → phi/4 Cos 2x/ cos x - sin x B. Lim x → 0 Cos x cos 3x / 1 - cos 2x

Limit bentuk 0/0

a. lim(x-> pi/4)  (cos 2x )/(cos x -sin x)
= lim(x->pi/4)  (cos x + sin x)(cos x - sin x)/(cos x -sin x)
= lim(x->pi/4) cos x + sin x
= cos pi/4 + sin pi/4
= 1/2 √2  + 1/2 √2
= √2

b. lim(x->0)  (cos 3x cos x) /(1- cos 2x)
x  =0
=  (cos 0. cos 0)/ (1 - cos0)
=  (1)(1) / (1 - 1)
= 1/0
= ∞