tolong di bantu ya.. makasih

jawab yng no 2 saja
 Luas ABCD = 50

AE = 2/3 ED
AE = 2x
ED = 3x
AD  = 5x = lebar = l = 5x

FC = 1/4 DF
FC = y
DF = 4y
CD = 5y = panjang = p= 5y


Luas ABCD = 50
p l = 50
5x . 5y = 50
25 xy = 50
x y = 2

.
Luas ABCD = Luas BFC + Luas BAE + Luas BEDF
50 = 1/2 (BC)(FC) + 1/2 (BA)(AE) + Luas BEDF
50 = 1/2 (5x)(y) + 1/2 (4y)(2x) + Luas BEDF
50 = 1/2 (5)(xy) + 4(xy) + Luas BEDF
50 = 1/2(5)(2) + 4(2) + Luas BDEF
50 = 5 + 8 + Luas BDEF
Luas BEDF = 50 - 13 = 37