Tolong bantu no 4 ya ..pake cara. Makasih

Deret hitung = aritmetika
deret ukur = geometri

deret hitung
a₁= 4.484
b = 1.234
un = bn + (a-b)
un₁ = 1.234 n + 3.250

deret ukur
u10/u5 = 118.098/486
r⁵ = 243
r = 3

u5 = 486 --> ar⁴ = 486
a = 486/(3⁴)
a₂ = 6

un₂ = arⁿ⁻¹ = 6. 3ⁿ⁻¹
un₂ = 6/3 . 3ⁿ
un₂ = 2. 3ⁿ

a)
un₁ = un₂
1.234 n + 3.250 = 2. 3ⁿ
617 n + 1./625 = 3ⁿ

3ⁿ - 617 n = 1.625
n = 8

b) a₁ = 4.484 , a₂ = 6
maka  a₁ > a₂