Jika a+b+c+d+e=17 dan a,b,c,d,e ganjil kemungkinan (a,b,c,d,e)=

Misalkan
a= 2j +1
b= 2k+1
c= 2l +1
d= 2m+1
e= 2n+1

Jadi,
2j+2k+2l+2m+2n+5=17
2(j+k+l+m+n)=12
j+k+l+m+n=6

Maka banyak kemungkinan ada
(6+5-1) C (5-1)= 10C4 = 10x3x7=210

Trims