jika f(2x-5)=6x-10 jika f(a^2)=56 berapa nilai a ?
Matematika
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Pertanyaan
jika f(2x-5)=6x-10 jika f(a^2)=56 berapa nilai a ?
1 Jawaban
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1. Jawaban whongaliem
f (2x - 5) = 6x - 10
f (x) = 6 (1/2 x + 5/2) - 10
= 3x + 15 - 10
= 3x + 5
f (a²) = 3a² + 5
56 = 3a² + 5
3a² = 56 - 5
3a² = 51
a² = 51/3
a² = 17
a = √17