Matematika

Pertanyaan

diketahui x + 3y =4 dan z= x.y nilai z akan maksimum jika

2 Jawaban

  • x + 3y = 4  ⇒ x = 4 - 3y

        z = x .y
          = (4 - 3y) y
          = 4y - 3y²    .. nilai maks  z jika z' = 0
      z' = 4 - 6y
      0 = 4 - 6y
    6y = 4
      y = 4/6
      y = 2/3

    x = 4 - 3y
      = 4 - 3 (2/3)
      = 4 - 2
      = 2

    z.maks = 2 . 2/3
                 = 4/3
  • x + 3y = 4 ⇒ x = 4 - 3y
    z = x .y
    = (4 - 3y) y
    = 4y - 3y² .. nilai maks z jika z' = 0
    z' = 4 - 6y
    0 = 4 - 6y
    6y = 4
    y = 4/6
    y = 2/3
    x = 4 - 3y
    = 4 - 3 (2/3)
    = 4 - 2
    = 2
    z.maks = 2 . 2/3
    = 4/3

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