Benda setinggi 6 cm di depan cermin cembung dng jarak 10 cm jika jarak titik api cermin 5 cm tentukan A.jarak bayangan B.perbesaran bayangan C.tinggi bayangan

diket :
h = 6 cm
s = 10 cm
f = 5 cm

dit :
s' = ...
M = ...
h' = ...

jawab:
1/f = 1/s + 1/s'
1/5 = 1/10 + 1/s'
1/s' = 1/5 - 1/10
1/s' = 2/10 - 1/10
1/s' = 1/10
s' = 10 cm

M = s'/s = 10/10 = 1 kali

M = h'/h
1 = h'/6
h' = 6 cm