Molalitas dari larutan 6 g CH3COOH yang dilarutkan dalam 200 g air adalah... ( A,C = 12H = 1,0 = 16 )

Mr CH3COOH = 12 + 3(1) + 12 + 16(2) + 1
= 12 + 3 + 12 + 32 + 1
= 60

M = gr/Mr × 1000/V
= 6/60 × 1000/200
= 1/10 × 5
= 5/10
= 0,5 M

Bab Stoikiometri
Kimia SMA Kelas X



w2 = 6 gram
Mr CH3COOH = 60
w1 = 200 gram

m = n x 1000 / w1
= 6 / 60 x 1000 / 200
= 0,1 x 5
= 0,5 molal

Semoga membantu yaaaa;)