Bantuin Selesaikan Pr Kimia Guy's no.1 pakai Cara ya Guys

maaf jika ada yg salah...

[OH⁻] = √Kw/Ka x M
[OH⁻] = √10⁻¹⁴/6,8.10⁻⁴ x 65.10⁻³
[OH⁻] = √9,55. 10⁻¹³
[OH⁻] = √95,5. 10⁻¹⁴
[OH⁻] = 9,77. 10⁻⁷

pOH = - log 9,77. 10⁻⁷
pOH = 7-log 9,77
pH = 14-(7-log 9,77)
pH = 7+log 9,77
pH = 7,98