100 mL larutan HCl 0,1 M dicampurkan dengan 100 mL larutan Ba(OH)2 0,05 M. pH larutan tersebut adalah??

HCl + BaOH ==> BaCl2 + H2O (belum setara)
2HCl + BaOH ==> BaCl2 + 2H2O (sudah setara)

mol HCl = 2 x 0.01M x 0.1L = 0.002 mol
mol Ba(OH)2 = 0.01M x 0.1L = 0.001 mol

2HCl + Ba(OH)2 ==> BaCl2 + 2H2O
0.002. 0.001
0.001. 0.001
0.001. -

H+ = v. asam x sisa asam / V. camp
H+ = 1 x 0.001 / 0.2
H+ = 0.005 = 5 x 10^-3
pH = - log H+
pH = - log (5 x 10^-3)
pH = 3 - log 5