pada segitiga ABC,AB=2x cm,BC=(x+3)cm,AC=(3x-1)cm.jika kelilingnya=50cm,hitunglah panjang masing - masing sisi!

keliling segitiga adalah AB+BC+AC = 50cm
2x + x+3 + 3x-1 = 50
6x + 2 = 50
6x=48
x=8

Panjang AB= 2(8) = 16
Panjang BC= 8+3 = 11
Panjang AC= 3(8)-1= 23

50 = 2x + x + 3 + 3x - 1
50 = 6x + 2
50 - 2 = 6x
48 = 6x
x = 8


AB = 2x
AB = 2 × 8
AB = 16

BC = x + 3
BC = 8 + 3
BC = 11

AC = 3x - 1
AC = (3 × 8) - 1
AC = 24 - 1
AC = 23