Persamaan x2+7x-20=0 mempunyai akat-akar x1 dan x2. Persamaan kuadrat baru yang akar akarnya y1=x1+2 dan y2=x2+2 adalah.. tolong jawab pakai cara.

x²+7x-20 = 0
• x1+x2 = -7
• x1.x2 = -20

y1+y2
= x1+2 + x2+2
= x1+x2+4
= (-7)+4
= -3

y1.y2
= (x1+2)(x2+2)
= x1.x2 + 2(x1+x2) + 4
= (-20) + 2(-7) + 4
= -30


Pers. kudrat barunya :
x² - (y1+y2)x + (y1.y2) = 0
x² - (-3)x + (-30) = 0
x² + 3x - 30 = 0