tolong bantu kerjakan no. 6 terimakasih.

Lim (x - 8)/(3√x - 2) = Lim (x - 8)/(x^1/3 - 2)

Cara L'HOSPITAL
Lim (x - 1)/(x^1/3 - 2)
= Lim 1 / (1/3 x^-2/3)
= Lim 3x^(2/3)
= 3(8)^2/3
= 3(2^3(2/3))
= 3(2^2)
= 12

Cara pemfaktoran
Lim (x - 8)/(x^1/3 - 2)
= Lim (x - 8)/(x^1/3 - 2) . (x^2/3 + 2x^1/3 + 4)/(x^2/3 + 2x^1/3 + 4)
= Lim (x - 8)(x^2/3 + 2x^1/3 + 4) / (x - 8)
= Lim (x^2/3 + 2x^1/3 + 4)
= (8)^2/3 + 2(8)^1/3 + 4)
= (2^3)^2/3 + 2(2^3)^1/3 + 4
= 2^2 + 2(2) + 4
= 4 + 4 + 4
= 12

^ = pangkat