tentukan nilai variabel berikut= 1.3(5p+4)=6(3p-2) 2.5(x-2)=x+14 3.2m+12=38 4.8x+10=7x+2 5.(3x+5)+(x-9)<-20
Matematika
auliadwi21
Pertanyaan
tentukan nilai variabel berikut=
1.3(5p+4)=6(3p-2)
2.5(x-2)=x+14
3.2m+12=38
4.8x+10=7x+2
5.(3x+5)+(x-9)<-20
1.3(5p+4)=6(3p-2)
2.5(x-2)=x+14
3.2m+12=38
4.8x+10=7x+2
5.(3x+5)+(x-9)<-20
2 Jawaban
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1. Jawaban weningd
1. 15p + 12 = 18p - 12
15p - 18p = -12 - 12
-3p = -24
p = -24 : -3 = 6
2. 5x - 10 = x + 14
5x - x = 14 + 10
4x = 24
x = 26
3. 2m + 12 = 38
2m = 38 - 12
2m = 26
m = 13
4. 8x + 10 = 7x + 2
8x - 7x = 2 - 10
x = -8
5. 3x + x + 5 - 9 < -20
4x - 4 < -20
4x < -20 + 4
4x < -16
x < -4 -
2. Jawaban amandafebriyenti
1.23p
2.6x+4
3.m=13
4.5x=4
5.-19x-45
kalo aku segitu ^_^