Besar <ACB adalah....

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  • 3x-40+x+84 = 180
    4x = 180-84+40
    x = 136/4
    x = 34

    <ACD = x+84 = 34+84 = 118
    <ACB = 54+x = 118
    <ACB = x = 118-54 = 64

  • <ACB + <ACD = 180

    180 = (3x - 40 )+ (x + 84)

    180 = 4x + 44

    4x = 180 - 44

    4x = 136

    x = 136/4 = 34 derajat

     

    <ACB = 3x - 40

    <ACB = 3.(34) - 40

    <ACB = 102 - 40 = 62 derajat


    180 = <BAC + < ACB + < ABC

    180 = 54 + 62 + <ABC
    <ABC = 180 - 116

    <ABC = 64 derajat


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