Volume sebuah balok 1800cm pangkat 3.panjangnya=15cm,dan lebarnya=6cm.hitunglah luas permukaan balok

V=plt
1800=15x6xt
1800=240xt
1800/240=t
7,5cm=t

Lp=2(pl+pt+lt)
=2(15x6+15x7,5+6x7,5)
=2(90+112,5+45)
=2x247,5
495cm²

V = p x l x t
1800 = 15 × 6 × t
1800 = 90t
t = 20
L = 2 (pl) + 2 (pt) + 2 (lt)
L = 2 (15×6) + 2(15×20) + 2(6×12)
L = 2(90) + 2(300)+2(72)
L = 180 + 600 +144
L = 924 cm^2