Diketahui harga PH larutan jenuh Mn (OH)2 adalah 9+log 4 berapakah harga Ksp Mn (OH)

Kelarutan & Hasilkali Kelarutan
Kimia XI

Basa Mn(OH)2
Nilai pH = 9 + log 4
pOH = 14 - pH
pOH = 5 - log 4
[OH^-] = 4 x 10^-5

Misalkan kelarutan = s (mol/liter)

Mn(OH)2 <=> Mn^2+ + 2OH^-
.......s......................s................2s
......................[2 x 10^-5]....[4 x 10^-5]

Ksp = [Mn^2+] [OH^-]^2
Ksp = [2 x 10^-5] [4 x 10^-5]^2

Ksp = 32 x 10^-15

Ksp = 3,2 x 10^-14